Strangly I didn't find the rule for this problem:
What do you do when you do not have enough bullets for a shot. For exemple 5 bullets for 2 bursts of 3 bullets?
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half empty magazin
Tue, 2016-04-19 06:55
#1
half empty magazin
Tue, 2016-04-19 07:26
#2
Ah, you need to check real
Ah, you need to check real life for this one. Law of Conservation of Mass for kinetic weapons and Law of Conservation of Energy for energy weapons should take care of you here.
But the quick and simple answer is just that you can't shoot two bursts of three bullets with only five bullets in the magazine.
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Tue, 2016-04-19 07:33
#3
So two thinks could happen:
So two thinks could happen:
1) you only shoot one burst and 2 bullets stay in the mag. Let's say the weapon has some kind of bullet counter that suppresses the second burst.
2) The second bust has only 2 bullets and i take damage×2/3
If it was only 4 bullets, the second burst could only hit 1 target and i calculate damage/3
Tue, 2016-04-19 07:41
#4
No. 1 would be very
No. 1 would be very unconvienient if you use a 10bullet magazin on FA
Tue, 2016-04-19 09:26
#5
its pretty simple, you take a
its pretty simple, you take a damage penalty how many buillets are left over how many are needed for the fire mode multiplied by the damage result on the dice roll
Tue, 2016-04-19 09:55
#6
Thank. That makes sense. But
Thanks. That makes sense. But not if you try to hit 2 targets with only one bullet left. So in that case you would only be able to take one target in SA for exemple