I have some trouble understanding the rules of brute-force hacking. I've translated the Hacking Cheat Sheet into Polish, and I've realized that 'ordinary' hacking requires two rolls, while brute-force hacking requires only one roll. Is this corrent?
The confusion stems from the fact that an ordinary hack has to defeat the firewall first (one roll). If there is no active monitoring, then it gains either the Covert (Normal Success) or Hidden (Extraordinary Success) status. If the system is actively monitored, the hacker has to make an Opposed Roll against the monitoring party, which can lead to either of four statuses (Hidden, Covert, Spotted, Locked).
Still, the section concerning brute-force suggests that the hacker makes a roll with +30 modifier (since they are facing the target head-on), but if the target is actively monitored, they have to make an Opposed roll, and they either end up with Locked status or kicked out of the system. Is the Opposed roll a SECOND roll, or is it the first roll (which would mean that it benefits from the +30 modifier)? Or are there two rolls, and do both benefit from the +30 modifier?
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Brute-force hacking - one roll or two rolls?
Tue, 2013-12-10 19:24
#1
Brute-force hacking - one roll or two rolls?
"Democracy is two wolves and a lamb voting on what to have for lunch. Liberty is a well-armed lamb contesting the vote." -Benjamin Franklin
"Democracy is two wolves and a lamb voting on what to have for lunch. Liberty is a well-armed lamb contesting the vote." -Benjamin Franklin